题号题目核心考点496下一个更大元素 I单调栈 + Map 缓存739每日温度下一个更大 + 存索引算距离503下一个更大元素 II循环数组（2 倍长度 + 取模）1019链表中的下一个更大节点链表转数组 + 模板1944队列中可以看到的人数弹栈计数 + 栈顶是否可见1475商品折扣后的最终价格右侧第一个 ≤ cur901股票价格跨度上一个更大（正序）402移掉 K 位数字单调递增栈 + k 限制853车队排序 + 时间比较（可不用栈）581最短无序连续子数组边界 + 最值扩展（非纯单调栈）
void countingSortSimple(int arr[], int n, int max) {
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Of course, the glue code also has runtime costs. JavaScript objects must be allocated and garbage collected, strings must be re-encoded, structs must be deserialized. Some of this cost is inherent to any bindings system, but much of it is not. This is a pervasive cost that you pay at the boundary between JavaScript and WebAssembly, even when the calls themselves are fast.，推荐阅读爱思助手下载最新版本获取更多信息